Train and bird

Question:

A train leaves City X for City Y at 15 mph. At the very same time, a train leaves City Y for City X at 20 mph on the same track. At the same moment, a bird leaves the City X train station and flies towards the City Y train station at 25 mph. When the bird reaches the train from City Y, it immediately reverses direction. It then continues to fly at the same speed towards the train from City X, when it reverses its direction again, and so forth. The bird continues to do this until the trains collide. How far would the bird have traveled in the meantime?(Distance(X to Y)=70 miles)

.

.

C

A

P

T

A

I

N

I

N

T

E

R

V

I

E

W

.

.

Solution:

Calculate the relative velocity of Train from City X with respect of Train from City Y, so Vx=15-(-20)=35, Time Taken before collision= Distance Between City X and City Y which means T= 70/35=2 So, Distance traveled by bird=Time taken before collision*speed of bird which is 2*25= 50 miles.

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